9m-(2/4m)=13

Solution for 9m-(2/4m)=13 equation:

9m-(2/4m)=13

We move all terms to the left:

9m-(2/4m)-(13)=0


Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

9m-(+2/4m)-13=0

We get rid of parentheses

9m-2/4m-13=0

We multiply all the terms by the denominator


9m*4m-13*4m-2=0

Wy multiply elements

36m^2-52m-2=0

a = 36; b = -52; c = -2;
Δ = b2-4ac
Δ = -522-4·36·(-2)
Δ = 2992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2992}=\sqrt{16*187}=\sqrt{16}*\sqrt{187}=4\sqrt{187}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4\sqrt{187}}{2*36}=\frac{52-4\sqrt{187}}{72}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4\sqrt{187}}{2*36}=\frac{52+4\sqrt{187}}{72}
$