2(2r-1)/6+5=3(r+7)

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Solution for 2(2r-1)/6+5=3(r+7) equation: 



2(2r-1)/6+5=3(r+7)

We move all terms to the left:

2(2r-1)/6+5-(3(r+7))=0

We multiply all the terms by the denominator


2(2r-1)-((3(r+7)))*6+5*6=0

We add all the numbers together, and all the variables

2(2r-1)-((3(r+7)))*6+30=0

We multiply parentheses

4r-((3(r+7)))*6-2+30=0

We add all the numbers together, and all the variables

4r-((3(r+7)))*6+28=0

We move all terms containing r to the left, all other terms to the right

4r-((3(r+7)))*6=-28

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