2(2r+2)=3(2r-2)

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Solution for 2(2r+2)=3(2r-2) equation: 



2(2r+2)=3(2r-2)

We move all terms to the left:

2(2r+2)-(3(2r-2))=0

We multiply parentheses

4r-(3(2r-2))+4=0



We calculate terms in parentheses: -(3(2r-2)), so:

3(2r-2)

We multiply parentheses

6r-6

Back to the equation:

-(6r-6)



We get rid of parentheses

4r-6r+6+4=0

We add all the numbers together, and all the variables

-2r+10=0

We move all terms containing r to the left, all other terms to the right

-2r=-10

r=-10/-2

r=+5

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