4(2c-2)=2(3c+3)

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Solution for 4(2c-2)=2(3c+3) equation: 



4(2c-2)=2(3c+3)

We move all terms to the left:

4(2c-2)-(2(3c+3))=0

We multiply parentheses

8c-(2(3c+3))-8=0



We calculate terms in parentheses: -(2(3c+3)), so:

2(3c+3)

We multiply parentheses

6c+6

Back to the equation:

-(6c+6)



We get rid of parentheses

8c-6c-6-8=0

We add all the numbers together, and all the variables

2c-14=0

We move all terms containing c to the left, all other terms to the right

2c=14

c=14/2

c=7

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