2(2p-4)=3(p+12)

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Solution for 2(2p-4)=3(p+12) equation: 



2(2p-4)=3(p+12)

We move all terms to the left:

2(2p-4)-(3(p+12))=0

We multiply parentheses

4p-(3(p+12))-8=0



We calculate terms in parentheses: -(3(p+12)), so:

3(p+12)

We multiply parentheses

3p+36

Back to the equation:

-(3p+36)



We get rid of parentheses

4p-3p-36-8=0

We add all the numbers together, and all the variables

p-44=0

We move all terms containing p to the left, all other terms to the right

p=44

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