7x-3(x-4)=40

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Solution for 7x-3(x-4)=40 equation: 



7x-3(x-4)=40

We move all terms to the left:

7x-3(x-4)-(40)=0

We multiply parentheses

7x-3x+12-40=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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