2(2p+1+3p+2)=2(p+8+2p+3)

Solution for 2(2p+1+3p+2)=2(p+8+2p+3) equation:

2(2p+1+3p+2)=2(p+8+2p+3)

We move all terms to the left:

2(2p+1+3p+2)-(2(p+8+2p+3))=0

We add all the numbers together, and all the variables

2(5p+3)-(2(3p+11))=0

We multiply parentheses

10p-(2(3p+11))+6=0


We calculate terms in parentheses: -(2(3p+11)), so:

2(3p+11)

We multiply parentheses

6p+22

Back to the equation:

-(6p+22)


We get rid of parentheses

10p-6p-22+6=0

We add all the numbers together, and all the variables

4p-16=0

We move all terms containing p to the left, all other terms to the right

4p=16

p=16/4

p=4