-35=3+5(c+12)

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Solution for -35=3+5(c+12) equation: 



-35=3+5(c+12)

We move all terms to the left:

-35-(3+5(c+12))=0



We calculate terms in parentheses: -(3+5(c+12)), so:

3+5(c+12)

determiningTheFunctionDomain
5(c+12)+3

We multiply parentheses

5c+60+3

We add all the numbers together, and all the variables

5c+63

Back to the equation:

-(5c+63)



We get rid of parentheses

-5c-63-35=0

We add all the numbers together, and all the variables

-5c-98=0

We move all terms containing c to the left, all other terms to the right

-5c=98

c=98/-5

c=-19+3/5

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