2(2n+3)+5=2(n-3)

Solution for 2(2n+3)+5=2(n-3) equation:

2(2n+3)+5=2(n-3)

We move all terms to the left:

2(2n+3)+5-(2(n-3))=0

We multiply parentheses

4n-(2(n-3))+6+5=0


We calculate terms in parentheses: -(2(n-3)), so:

2(n-3)

We multiply parentheses

2n-6

Back to the equation:

-(2n-6)


We add all the numbers together, and all the variables

4n-(2n-6)+11=0

We get rid of parentheses

4n-2n+6+11=0

We add all the numbers together, and all the variables

2n+17=0

We move all terms containing n to the left, all other terms to the right

2n=-17

n=-17/2

n=-8+1/2