4x-3(20-x)=6x-7(11-3x)

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Solution for 4x-3(20-x)=6x-7(11-3x) equation: 



4x-3(20-x)=6x-7(11-3x)

We move all terms to the left:

4x-3(20-x)-(6x-7(11-3x))=0

We add all the numbers together, and all the variables

4x-3(-1x+20)-(6x-7(-3x+11))=0

We multiply parentheses

4x+3x-(6x-7(-3x+11))-60=0



We calculate terms in parentheses: -(6x-7(-3x+11)), so:

6x-7(-3x+11)

We multiply parentheses

6x+21x-77

We add all the numbers together, and all the variables

27x-77

Back to the equation:

-(27x-77)



We add all the numbers together, and all the variables

7x-(27x-77)-60=0

We get rid of parentheses

7x-27x+77-60=0

We add all the numbers together, and all the variables

-20x+17=0

We move all terms containing x to the left, all other terms to the right

-20x=-17

x=-17/-20

x=17/20

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