2(2m+3)-2m=4(m+10)

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Solution for 2(2m+3)-2m=4(m+10) equation: 



2(2m+3)-2m=4(m+10)

We move all terms to the left:

2(2m+3)-2m-(4(m+10))=0

We add all the numbers together, and all the variables

-2m+2(2m+3)-(4(m+10))=0

We multiply parentheses

-2m+4m-(4(m+10))+6=0



We calculate terms in parentheses: -(4(m+10)), so:

4(m+10)

We multiply parentheses

4m+40

Back to the equation:

-(4m+40)



We add all the numbers together, and all the variables

2m-(4m+40)+6=0

We get rid of parentheses

2m-4m-40+6=0

We add all the numbers together, and all the variables

-2m-34=0

We move all terms containing m to the left, all other terms to the right

-2m=34

m=34/-2

m=-17

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