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5(x+1)=2(x+3)+1
We move all terms to the left:
5(x+1)-(2(x+3)+1)=0
We multiply parentheses
5x-(2(x+3)+1)+5=0
We calculate terms in parentheses: -(2(x+3)+1), so:We get rid of parentheses
2(x+3)+1
We multiply parentheses
2x+6+1
We add all the numbers together, and all the variables
2x+7
Back to the equation:
-(2x+7)
5x-2x-7+5=0
We add all the numbers together, and all the variables
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3
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