2(2i-1)+4i=-7(i-4)

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Solution for 2(2i-1)+4i=-7(i-4) equation:



2(2i-1)+4i=-7(i-4)
We move all terms to the left:
2(2i-1)+4i-(-7(i-4))=0
We add all the numbers together, and all the variables
4i+2(2i-1)-(-7(i-4))=0
We multiply parentheses
4i+4i-(-7(i-4))-2=0
We calculate terms in parentheses: -(-7(i-4)), so:
-7(i-4)
We multiply parentheses
-7i+28
Back to the equation:
-(-7i+28)
We add all the numbers together, and all the variables
8i-(-7i+28)-2=0
We get rid of parentheses
8i+7i-28-2=0
We add all the numbers together, and all the variables
15i-30=0
We move all terms containing i to the left, all other terms to the right
15i=30
i=30/15
i=2

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