2(2i-1)+4i=7(i-4)

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Solution for 2(2i-1)+4i=7(i-4) equation: 



2(2i-1)+4i=7(i-4)

We move all terms to the left:

2(2i-1)+4i-(7(i-4))=0

We add all the numbers together, and all the variables

4i+2(2i-1)-(7(i-4))=0

We multiply parentheses

4i+4i-(7(i-4))-2=0



We calculate terms in parentheses: -(7(i-4)), so:

7(i-4)

We multiply parentheses

7i-28

Back to the equation:

-(7i-28)



We add all the numbers together, and all the variables

8i-(7i-28)-2=0

We get rid of parentheses

8i-7i+28-2=0

We add all the numbers together, and all the variables

i+26=0

We move all terms containing i to the left, all other terms to the right

i=-26

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