2(2h+2)=5(3h+3)-2h

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Solution for 2(2h+2)=5(3h+3)-2h equation: 



2(2h+2)=5(3h+3)-2h

We move all terms to the left:

2(2h+2)-(5(3h+3)-2h)=0

We multiply parentheses

4h-(5(3h+3)-2h)+4=0



We calculate terms in parentheses: -(5(3h+3)-2h), so:

5(3h+3)-2h

We add all the numbers together, and all the variables

-2h+5(3h+3)

We multiply parentheses

-2h+15h+15

We add all the numbers together, and all the variables

13h+15

Back to the equation:

-(13h+15)



We get rid of parentheses

4h-13h-15+4=0

We add all the numbers together, and all the variables

-9h-11=0

We move all terms containing h to the left, all other terms to the right

-9h=11

h=11/-9

h=-1+2/9

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