2(2a-5)+3a=1/7(49a-70)

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Solution for 2(2a-5)+3a=1/7(49a-70) equation: 



2(2a-5)+3a=1/7(49a-70)

We move all terms to the left:

2(2a-5)+3a-(1/7(49a-70))=0



Domain of the equation: 7(49a-70))!=0

a∈R



We add all the numbers together, and all the variables

3a+2(2a-5)-(1/7(49a-70))=0

We multiply parentheses

3a+4a-(1/7(49a-70))-10=0

We multiply all the terms by the denominator


3a*7(49a-70))+4a*7(49a-70))-(1-10*7(49a-70))=0

We add all the numbers together, and all the variables

3a*7(49a-70))+4a*7(49a-70))-(1-10*7(49a=0

Wy multiply elements

147a^3(4-70))-(1-10*7(49a=0

We do not support eapression: a^3(4

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