2(27-b)=100-4b+6(3b-b)

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Solution for 2(27-b)=100-4b+6(3b-b) equation:



2(27-b)=100-4b+6(3b-b)
We move all terms to the left:
2(27-b)-(100-4b+6(3b-b))=0
We add all the numbers together, and all the variables
2(-1b+27)-(100-4b+6(+2b))=0
We multiply parentheses
-2b-(100-4b+6(+2b))+54=0
We calculate terms in parentheses: -(100-4b+6(+2b)), so:
100-4b+6(+2b)
determiningTheFunctionDomain -4b+6(+2b)+100
We multiply parentheses
-4b+12b+100
We add all the numbers together, and all the variables
8b+100
Back to the equation:
-(8b+100)
We get rid of parentheses
-2b-8b-100+54=0
We add all the numbers together, and all the variables
-10b-46=0
We move all terms containing b to the left, all other terms to the right
-10b=46
b=46/-10
b=-4+3/5

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