(33/6)x=12

Solution for (33/6)x=12 equation:

(33/6)x=12

We move all terms to the left:

(33/6)x-(12)=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+33/6)x-12=0

We multiply parentheses

33x^2-12=0

a = 33; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·33·(-12)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*33}=\frac{0-12\sqrt{11}}{66}
=-\frac{12\sqrt{11}}{66}
=-\frac{2\sqrt{11}}{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*33}=\frac{0+12\sqrt{11}}{66}
=\frac{12\sqrt{11}}{66}
=\frac{2\sqrt{11}}{11}
$