2(27-b)=100-4b+6(3+M-b)

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Solution for 2(27-b)=100-4b+6(3+M-b) equation:



2(27-b)=100-4b+6(3+-b)
We move all terms to the left:
2(27-b)-(100-4b+6(3+-b))=0
We add all the numbers together, and all the variables
2(-1b+27)-(100-4b+6(-1b))=0
We multiply parentheses
-2b-(100-4b+6(-1b))+54=0
We calculate terms in parentheses: -(100-4b+6(-1b)), so:
100-4b+6(-1b)
determiningTheFunctionDomain -4b+6(-1b)+100
We multiply parentheses
-4b-6b+100
We add all the numbers together, and all the variables
-10b+100
Back to the equation:
-(-10b+100)
We get rid of parentheses
-2b+10b-100+54=0
We add all the numbers together, and all the variables
8b-46=0
We move all terms containing b to the left, all other terms to the right
8b=46
b=46/8
b=5+3/4

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