2(2-4b)=60-2b-3(3b+11)

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Solution for 2(2-4b)=60-2b-3(3b+11) equation: 



2(2-4b)=60-2b-3(3b+11)

We move all terms to the left:

2(2-4b)-(60-2b-3(3b+11))=0

We add all the numbers together, and all the variables

2(-4b+2)-(60-2b-3(3b+11))=0

We multiply parentheses

-8b-(60-2b-3(3b+11))+4=0



We calculate terms in parentheses: -(60-2b-3(3b+11)), so:

60-2b-3(3b+11)

determiningTheFunctionDomain
-2b-3(3b+11)+60

We multiply parentheses

-2b-9b-33+60

We add all the numbers together, and all the variables

-11b+27

Back to the equation:

-(-11b+27)



We get rid of parentheses

-8b+11b-27+4=0

We add all the numbers together, and all the variables

3b-23=0

We move all terms containing b to the left, all other terms to the right

3b=23

b=23/3

b=7+2/3

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