x2-160x+6400=0

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Solution for x2-160x+6400=0 equation: 



x2-160x+6400=0

We add all the numbers together, and all the variables

x^2-160x+6400=0

a = 1; b = -160; c = +6400;
Δ = b2-4ac
Δ = -1602-4·1·6400
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{160}{2}=80$

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