2(2-4)=5(r-7)

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Solution for 2(2-4)=5(r-7) equation:



2(2-4)=5(r-7)
We move all terms to the left:
2(2-4)-(5(r-7))=0
We add all the numbers together, and all the variables
-(5(r-7))+2(-2)=0
We add all the numbers together, and all the variables
-(5(r-7))-4=0
We calculate terms in parentheses: -(5(r-7)), so:
5(r-7)
We multiply parentheses
5r-35
Back to the equation:
-(5r-35)
We get rid of parentheses
-5r+35-4=0
We add all the numbers together, and all the variables
-5r+31=0
We move all terms containing r to the left, all other terms to the right
-5r=-31
r=-31/-5
r=6+1/5

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