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2(2(2+x))+2=2+2+2+(2+6x)
We move all terms to the left:
2(2(2+x))+2-(2+2+2+(2+6x))=0
We add all the numbers together, and all the variables
2(2(x+2))-(2+2+2+(6x+2))+2=0
We calculate terms in parentheses: -(2+2+2+(6x+2)), so:We get rid of parentheses
2+2+2+(6x+2)
determiningTheFunctionDomain (6x+2)+2+2+2
We add all the numbers together, and all the variables
(6x+2)+6
We get rid of parentheses
6x+2+6
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
2(2(x+2))-6x-8+2=0
We add all the numbers together, and all the variables
-6x+2(2(x+2))-6=0
We move all terms containing x to the left, all other terms to the right
-6x+2(2(x+2))=6
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