2(3y+2)=18y-32

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Solution for 2(3y+2)=18y-32 equation: 



2(3y+2)=18y-32

We move all terms to the left:

2(3y+2)-(18y-32)=0

We multiply parentheses

6y-(18y-32)+4=0

We get rid of parentheses

6y-18y+32+4=0

We add all the numbers together, and all the variables

-12y+36=0

We move all terms containing y to the left, all other terms to the right

-12y=-36

y=-36/-12

y=+3

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