2(1y-6)=20

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Solution for 2(1y-6)=20 equation: 



2(1y-6)=20

We move all terms to the left:

2(1y-6)-(20)=0

We add all the numbers together, and all the variables

2(y-6)-20=0

We multiply parentheses

2y-12-20=0

We add all the numbers together, and all the variables

2y-32=0

We move all terms containing y to the left, all other terms to the right

2y=32

y=32/2

y=16

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