-5(-2-3x)=2(-2x-4)+3x

Solution for -5(-2-3x)=2(-2x-4)+3x equation:

-5(-2-3x)=2(-2x-4)+3x

We move all terms to the left:

-5(-2-3x)-(2(-2x-4)+3x)=0

We add all the numbers together, and all the variables

-5(-3x-2)-(2(-2x-4)+3x)=0

We multiply parentheses

15x-(2(-2x-4)+3x)+10=0


We calculate terms in parentheses: -(2(-2x-4)+3x), so:

2(-2x-4)+3x

We add all the numbers together, and all the variables

3x+2(-2x-4)

We multiply parentheses

3x-4x-8

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)


We get rid of parentheses

15x+1x+8+10=0

We add all the numbers together, and all the variables

16x+18=0

We move all terms containing x to the left, all other terms to the right

16x=-18

x=-18/16

x=-1+1/8