2(1x2)=5+5

Solution for 2(1x2)=5+5 equation:

2(1x^2)=5+5

We move all terms to the left:

2(1x^2)-(5+5)=0

We add all the numbers together, and all the variables

21x^2-10=0

a = 21; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·21·(-10)
Δ = 840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{840}=\sqrt{4*210}=\sqrt{4}*\sqrt{210}=2\sqrt{210}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{210}}{2*21}=\frac{0-2\sqrt{210}}{42}
=-\frac{2\sqrt{210}}{42}
=-\frac{\sqrt{210}}{21}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{210}}{2*21}=\frac{0+2\sqrt{210}}{42}
=\frac{2\sqrt{210}}{42}
=\frac{\sqrt{210}}{21}
$