-3(11b+5)=6(8-2b)

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Solution for -3(11b+5)=6(8-2b) equation: 



-3(11b+5)=6(8-2b)

We move all terms to the left:

-3(11b+5)-(6(8-2b))=0

We add all the numbers together, and all the variables

-3(11b+5)-(6(-2b+8))=0

We multiply parentheses

-33b-(6(-2b+8))-15=0



We calculate terms in parentheses: -(6(-2b+8)), so:

6(-2b+8)

We multiply parentheses

-12b+48

Back to the equation:

-(-12b+48)



We get rid of parentheses

-33b+12b-48-15=0

We add all the numbers together, and all the variables

-21b-63=0

We move all terms containing b to the left, all other terms to the right

-21b=63

b=63/-21

b=-3

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