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(1-x)*x=0.2
We move all terms to the left:
(1-x)*x-(0.2)=0
We add all the numbers together, and all the variables
(-1x+1)*x-(0.2)=0
We add all the numbers together, and all the variables
(-1x+1)*x-0.2=0
We multiply parentheses
-1x^2+x-0.2=0
a = -1; b = 1; c = -0.2;
Δ = b2-4ac
Δ = 12-4·(-1)·(-0.2)
Δ = 0.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.2}}{2*-1}=\frac{-1-\sqrt{0.2}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.2}}{2*-1}=\frac{-1+\sqrt{0.2}}{-2} $
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