2(1x+4)=-4x(-1x+4)

Solution for 2(1x+4)=-4x(-1x+4) equation:

2(1x+4)=-4x(-1x+4)

We move all terms to the left:

2(1x+4)-(-4x(-1x+4))=0

We add all the numbers together, and all the variables

2(x+4)-(-4x(-1x+4))=0

We multiply parentheses

2x-(-4x(-1x+4))+8=0


We calculate terms in parentheses: -(-4x(-1x+4)), so:

-4x(-1x+4)

We multiply parentheses

4x^2-16x

Back to the equation:

-(4x^2-16x)


We get rid of parentheses

-4x^2+2x+16x+8=0

We add all the numbers together, and all the variables

-4x^2+18x+8=0

a = -4; b = 18; c = +8;
Δ = b2-4ac
Δ = 182-4·(-4)·8
Δ = 452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{452}=\sqrt{4*113}=\sqrt{4}*\sqrt{113}=2\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{113}}{2*-4}=\frac{-18-2\sqrt{113}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{113}}{2*-4}=\frac{-18+2\sqrt{113}}{-8}
$