2(11n-3)=40-n

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Solution for 2(11n-3)=40-n equation: 



2(11n-3)=40-n

We move all terms to the left:

2(11n-3)-(40-n)=0

We add all the numbers together, and all the variables

2(11n-3)-(-1n+40)=0

We multiply parentheses

22n-(-1n+40)-6=0

We get rid of parentheses

22n+1n-40-6=0

We add all the numbers together, and all the variables

23n-46=0

We move all terms containing n to the left, all other terms to the right

23n=46

n=46/23

n=2

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