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3(x-5)+10=2(x-5)
We move all terms to the left:
3(x-5)+10-(2(x-5))=0
We multiply parentheses
3x-(2(x-5))-15+10=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
3x-(2x-10)-5=0
We get rid of parentheses
3x-2x+10-5=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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