2(1/2x+1)+6(x-3)=19

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Solution for 2(1/2x+1)+6(x-3)=19 equation: 



2(1/2x+1)+6(x-3)=19

We move all terms to the left:

2(1/2x+1)+6(x-3)-(19)=0



Domain of the equation: 2x+1)!=0

x∈R



We multiply parentheses

2x+6x+2-18-19=0

We add all the numbers together, and all the variables

8x-35=0

We move all terms containing x to the left, all other terms to the right

8x=35

x=35/8

x=4+3/8

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