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1x+2/3x=230
We move all terms to the left:
1x+2/3x-(230)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+2/3x-230=0
We multiply all the terms by the denominator
x*3x-230*3x+2=0
Wy multiply elements
3x^2-690x+2=0
a = 3; b = -690; c = +2;
Δ = b2-4ac
Δ = -6902-4·3·2
Δ = 476076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{476076}=\sqrt{4*119019}=\sqrt{4}*\sqrt{119019}=2\sqrt{119019}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-690)-2\sqrt{119019}}{2*3}=\frac{690-2\sqrt{119019}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-690)+2\sqrt{119019}}{2*3}=\frac{690+2\sqrt{119019}}{6} $
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