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2(1/2)p=100.6
We move all terms to the left:
2(1/2)p-(100.6)=0
Domain of the equation: 2)p!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
2(+1/2)p-(100.6)=0
We add all the numbers together, and all the variables
2(+1/2)p-100.6=0
We multiply parentheses
2p^2-100.6=0
a = 2; b = 0; c = -100.6;
Δ = b2-4ac
Δ = 02-4·2·(-100.6)
Δ = 804.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{804.8}}{2*2}=\frac{0-\sqrt{804.8}}{4} =-\frac{\sqrt{}}{4} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{804.8}}{2*2}=\frac{0+\sqrt{804.8}}{4} =\frac{\sqrt{}}{4} $
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