3(a+5)=4(a+5)+(a+5)

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Solution for 3(a+5)=4(a+5)+(a+5) equation: 



3(a+5)=4(a+5)+(a+5)

We move all terms to the left:

3(a+5)-(4(a+5)+(a+5))=0

We multiply parentheses

3a-(4(a+5)+(a+5))+15=0



We calculate terms in parentheses: -(4(a+5)+(a+5)), so:

4(a+5)+(a+5)

We multiply parentheses

4a+(a+5)+20

We get rid of parentheses

4a+a+5+20

We add all the numbers together, and all the variables

5a+25

Back to the equation:

-(5a+25)



We get rid of parentheses

3a-5a-25+15=0

We add all the numbers together, and all the variables

-2a-10=0

We move all terms containing a to the left, all other terms to the right

-2a=10

a=10/-2

a=-5

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