2(1-x)=3(3+2x)+6

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Solution for 2(1-x)=3(3+2x)+6 equation: 



2(1-x)=3(3+2x)+6

We move all terms to the left:

2(1-x)-(3(3+2x)+6)=0

We add all the numbers together, and all the variables

2(-1x+1)-(3(2x+3)+6)=0

We multiply parentheses

-2x-(3(2x+3)+6)+2=0



We calculate terms in parentheses: -(3(2x+3)+6), so:

3(2x+3)+6

We multiply parentheses

6x+9+6

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

-2x-6x-15+2=0

We add all the numbers together, and all the variables

-8x-13=0

We move all terms containing x to the left, all other terms to the right

-8x=13

x=13/-8

x=-1+5/8

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