4y-3(3y-4)=2-4(-1-y)

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Solution for 4y-3(3y-4)=2-4(-1-y) equation: 



4y-3(3y-4)=2-4(-1-y)

We move all terms to the left:

4y-3(3y-4)-(2-4(-1-y))=0

We add all the numbers together, and all the variables

4y-3(3y-4)-(2-4(-1y-1))=0

We multiply parentheses

4y-9y-(2-4(-1y-1))+12=0



We calculate terms in parentheses: -(2-4(-1y-1)), so:

2-4(-1y-1)

determiningTheFunctionDomain
-4(-1y-1)+2

We multiply parentheses

4y+4+2

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We add all the numbers together, and all the variables

-5y-(4y+6)+12=0

We get rid of parentheses

-5y-4y-6+12=0

We add all the numbers together, and all the variables

-9y+6=0

We move all terms containing y to the left, all other terms to the right

-9y=-6

y=-6/-9

y=2/3

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