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2(1-5x)=3(3x+1)
We move all terms to the left:
2(1-5x)-(3(3x+1))=0
We add all the numbers together, and all the variables
2(-5x+1)-(3(3x+1))=0
We multiply parentheses
-10x-(3(3x+1))+2=0
We calculate terms in parentheses: -(3(3x+1)), so:We get rid of parentheses
3(3x+1)
We multiply parentheses
9x+3
Back to the equation:
-(9x+3)
-10x-9x-3+2=0
We add all the numbers together, and all the variables
-19x-1=0
We move all terms containing x to the left, all other terms to the right
-19x=1
x=1/-19
x=-1/19
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