5(x+1)=2(x+4)+7x

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Solution for 5(x+1)=2(x+4)+7x equation: 



5(x+1)=2(x+4)+7x

We move all terms to the left:

5(x+1)-(2(x+4)+7x)=0

We multiply parentheses

5x-(2(x+4)+7x)+5=0



We calculate terms in parentheses: -(2(x+4)+7x), so:

2(x+4)+7x

We add all the numbers together, and all the variables

7x+2(x+4)

We multiply parentheses

7x+2x+8

We add all the numbers together, and all the variables

9x+8

Back to the equation:

-(9x+8)



We get rid of parentheses

5x-9x-8+5=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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