2(1+4n)-4(3n+3)=1-4n+1+3n

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Solution for 2(1+4n)-4(3n+3)=1-4n+1+3n equation: 



2(1+4n)-4(3n+3)=1-4n+1+3n

We move all terms to the left:

2(1+4n)-4(3n+3)-(1-4n+1+3n)=0

We add all the numbers together, and all the variables

2(4n+1)-4(3n+3)-(-1n+2)=0

We multiply parentheses

8n-12n-(-1n+2)+2-12=0

We get rid of parentheses

8n-12n+1n-2+2-12=0

We add all the numbers together, and all the variables

-3n-12=0

We move all terms containing n to the left, all other terms to the right

-3n=12

n=12/-3

n=-4

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