2(-7z+2)=2(-10z-4)-6z

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Solution for 2(-7z+2)=2(-10z-4)-6z equation: 



2(-7z+2)=2(-10z-4)-6z

We move all terms to the left:

2(-7z+2)-(2(-10z-4)-6z)=0

We multiply parentheses

-14z-(2(-10z-4)-6z)+4=0



We calculate terms in parentheses: -(2(-10z-4)-6z), so:

2(-10z-4)-6z

We add all the numbers together, and all the variables

-6z+2(-10z-4)

We multiply parentheses

-6z-20z-8

We add all the numbers together, and all the variables

-26z-8

Back to the equation:

-(-26z-8)



We get rid of parentheses

-14z+26z+8+4=0

We add all the numbers together, and all the variables

12z+12=0

We move all terms containing z to the left, all other terms to the right

12z=-12

z=-12/12

z=-1

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