3(6c-3)=-3(-7+4c)

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Solution for 3(6c-3)=-3(-7+4c) equation: 



3(6c-3)=-3(-7+4c)

We move all terms to the left:

3(6c-3)-(-3(-7+4c))=0

We add all the numbers together, and all the variables

3(6c-3)-(-3(4c-7))=0

We multiply parentheses

18c-(-3(4c-7))-9=0



We calculate terms in parentheses: -(-3(4c-7)), so:

-3(4c-7)

We multiply parentheses

-12c+21

Back to the equation:

-(-12c+21)



We get rid of parentheses

18c+12c-21-9=0

We add all the numbers together, and all the variables

30c-30=0

We move all terms containing c to the left, all other terms to the right

30c=30

c=30/30

c=1

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