2(-4)-5(2z-5)=-(3z+50)

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Solution for 2(-4)-5(2z-5)=-(3z+50) equation: 



2(-4)-5(2z-5)=-(3z+50)

We move all terms to the left:

2(-4)-5(2z-5)-(-(3z+50))=0

We add all the numbers together, and all the variables

-5(2z-5)-(-(3z+50))-8=0

We multiply parentheses

-10z-(-(3z+50))+25-8=0



We calculate terms in parentheses: -(-(3z+50)), so:

-(3z+50)

We get rid of parentheses

-3z-50

Back to the equation:

-(-3z-50)



We add all the numbers together, and all the variables

-10z-(-3z-50)+17=0

We get rid of parentheses

-10z+3z+50+17=0

We add all the numbers together, and all the variables

-7z+67=0

We move all terms containing z to the left, all other terms to the right

-7z=-67

z=-67/-7

z=9+4/7

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