5(-3x+x)=-(4-x)+(-21+2x)

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Solution for 5(-3x+x)=-(4-x)+(-21+2x) equation: 



5(-3x+x)=-(4-x)+(-21+2x)

We move all terms to the left:

5(-3x+x)-(-(4-x)+(-21+2x))=0

We add all the numbers together, and all the variables

5(-2x)-(-(-1x+4)+(2x-21))=0

We multiply parentheses

-10x-(-(-1x+4)+(2x-21))=0



We calculate terms in parentheses: -(-(-1x+4)+(2x-21)), so:

-(-1x+4)+(2x-21)

We get rid of parentheses

1x+2x-4-21

We add all the numbers together, and all the variables

3x-25

Back to the equation:

-(3x-25)



We get rid of parentheses

-10x-3x+25=0

We add all the numbers together, and all the variables

-13x+25=0

We move all terms containing x to the left, all other terms to the right

-13x=-25

x=-25/-13

x=1+12/13

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