2(-10b+5)-4b=7(-b-1)

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Solution for 2(-10b+5)-4b=7(-b-1) equation: 



2(-10b+5)-4b=7(-b-1)

We move all terms to the left:

2(-10b+5)-4b-(7(-b-1))=0

We add all the numbers together, and all the variables

2(-10b+5)-4b-(7(-1b-1))=0

We add all the numbers together, and all the variables

-4b+2(-10b+5)-(7(-1b-1))=0

We multiply parentheses

-4b-20b-(7(-1b-1))+10=0



We calculate terms in parentheses: -(7(-1b-1)), so:

7(-1b-1)

We multiply parentheses

-7b-7

Back to the equation:

-(-7b-7)



We add all the numbers together, and all the variables

-24b-(-7b-7)+10=0

We get rid of parentheses

-24b+7b+7+10=0

We add all the numbers together, and all the variables

-17b+17=0

We move all terms containing b to the left, all other terms to the right

-17b=-17

b=-17/-17

b=1

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