(x-6)+1=2(x-10)-3

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Solution for (x-6)+1=2(x-10)-3 equation: 



(x-6)+1=2(x-10)-3

We move all terms to the left:

(x-6)+1-(2(x-10)-3)=0

We get rid of parentheses

x-(2(x-10)-3)-6+1=0



We calculate terms in parentheses: -(2(x-10)-3), so:

2(x-10)-3

We multiply parentheses

2x-20-3

We add all the numbers together, and all the variables

2x-23

Back to the equation:

-(2x-23)



We add all the numbers together, and all the variables

x-(2x-23)-5=0

We get rid of parentheses

x-2x+23-5=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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