1z+3(1z-7)=19

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Solution for 1z+3(1z-7)=19 equation: 



1z+3(1z-7)=19

We move all terms to the left:

1z+3(1z-7)-(19)=0

We add all the numbers together, and all the variables

1z+3(z-7)-19=0

We add all the numbers together, and all the variables

z+3(z-7)-19=0

We multiply parentheses

z+3z-21-19=0

We add all the numbers together, and all the variables

4z-40=0

We move all terms containing z to the left, all other terms to the right

4z=40

z=40/4

z=10

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