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(2x-17)/(x+1)=x+5
We move all terms to the left:
(2x-17)/(x+1)-(x+5)=0
Domain of the equation: (x+1)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(2x-17)/(x+1)-x-5=0
We multiply all the terms by the denominator
(2x-17)-x*(x+1)-5*(x+1)=0
We multiply parentheses
-x^2+(2x-17)-x-5x-5=0
We get rid of parentheses
-x^2+2x-x-5x-17-5=0
We add all the numbers together, and all the variables
-1x^2-4x-22=0
a = -1; b = -4; c = -22;
Δ = b2-4ac
Δ = -42-4·(-1)·(-22)
Δ = -72
Delta is less than zero, so there is no solution for the equation
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