1x+3=65x2

Solution for 1x+3=65x2 equation:

1x+3=65x^2

We move all terms to the left:

1x+3-(65x^2)=0

determiningTheFunctionDomain
-65x^2+1x+3=0

We add all the numbers together, and all the variables

-65x^2+x+3=0

a = -65; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-65)·3
Δ = 781
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{781}}{2*-65}=\frac{-1-\sqrt{781}}{-130}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{781}}{2*-65}=\frac{-1+\sqrt{781}}{-130}
$